Problem

QUESTION 6

Solve the equation.
\[
v(15 v-11)=-2
\]
a) $v=\frac{2}{5} ; v=\frac{1}{3}$
b) $v=0 ; v=\frac{11}{15}$
c) $v=-\frac{2}{5} ; v=-\frac{1}{3}$
d) $v=\frac{2}{5} ; v=-\frac{1}{3}$
a..
b..
c..
d..

QUESTION 7

Answer

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Answer

Therefore, the correct answer is \(v = \frac{2}{3}\) or \(v = \frac{1}{5}\)

Steps

Step 1 :Expand the equation: \(15v^2 - 11v = -2\)

Step 2 :Rearrange the equation: \(15v^2 - 11v + 2 = 0\)

Step 3 :Factor the quadratic equation: \((3v-2)(5v-1) = 0\)

Step 4 :Set each factor equal to zero: \(3v-2 = 0\) or \(5v-1 = 0\)

Step 5 :Solve for \(v\) in each equation: \(v = \frac{2}{3}\) or \(v = \frac{1}{5}\)

Step 6 :Therefore, the correct answer is \(v = \frac{2}{3}\) or \(v = \frac{1}{5}\)

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