Suppose $\int_{2}^{4} f(x) d x=-5, \int_{2}^{7} f(x) d x=-4$, and $\int_{2}^{7} g(x) d x=2$. Evaluate the following integrals.
\[
\int_{7}^{2} g(x) d x=
\]
(Simplify your answer.)

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Final Answer: The value of the integral $\int_{7}^{2} g(x) d x$ is $\boxed{-2}$.

Steps

Step 1 ：Suppose we have the integral of a function g(x) from 2 to 7, denoted as $\int_{2}^{7} g(x) d x=2$.

Step 2 ：The integral of a function from a to b is the negative of the integral from b to a. This is a property of definite integrals.

Step 3 ：Therefore, the integral of g(x) from 7 to 2 is the negative of the integral of g(x) from 2 to 7.

Step 4 ：Substituting the given value, we get $\int_{7}^{2} g(x) d x = -2$.

Step 5 ：Final Answer: The value of the integral $\int_{7}^{2} g(x) d x$ is $\boxed{-2}$.