Factorize the following polynomial using the difference of squares method: (x^2 - 9)

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Accepted Answer

Step:1 ：First, identify if the polynomial is a difference of squares. This means the polynomial should be in the form (a^2 - b^2).Step:2 ：In the polynomial (x^2 - 9), (a = x) and (b = 3) because (x^2 = (x)^2) and (9 = (3)^2). So, it is a difference of squares.Step:3 ：Now, use the formula for factoring a difference of squares, which is (a^2 - b^2 = (a - b)(a + b)).Step:4 ：Substitute (a = x) and (b = 3) into the formula to get the factors. So, (x^2 - 9 = (x - 3)(x + 3)).

Answer

Step: 1 ：First, identify if the polynomial is a difference of squares. This means the polynomial should be in the form (a^2 - b^2).Step: 2 ：In the polynomial (x^2 - 9), (a = x) and (b = 3) because (x^2 = (x)^2) and (9 = (3)^2). So, it is a difference of squares.Step: 3 ：Now, use the formula for factoring a difference of squares, which is (a^2 - b^2 = (a - b)(a + b)).Step: 4 ：Substitute (a = x) and (b = 3) into the formula to get the factors. So, (x^2 - 9 = (x - 3)(x + 3)).

Factorize the following polynomial using the difference of squares method: \(x^2 - 9\)

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