Use the logistic growth model $f(x)=\frac{230}{1+5 e^{-2 x}}$.
Find $f(0)$. Round to the nearest tenth.
Interpret $f(0)$.
$f(0)$ represents the carrying capacity.
$f(0)$ represents the final amount.
$f(0)$ represents the rate of growth.
$f(0)$ represents the initial amount.
$f(0)$ represents the half life.
Final Answer: \(f(0)\) is \(\boxed{38.3}\) and it represents the initial amount.
Step 1 :Use the logistic growth model \(f(x)=\frac{230}{1+5 e^{-2 x}}\).
Step 2 :Find \(f(0)\).
Step 3 :Calculate \(f(0)\) by substituting \(x = 0\) into the equation, which gives \(f(0) = \frac{230}{1+5 e^{0}}\).
Step 4 :Calculate the value of \(f(0)\) to get \(f(0) = 38.333333333333336\).
Step 5 :Round \(f(0)\) to the nearest tenth to get \(f(0) = 38.3\).
Step 6 :Interpret \(f(0)\). In the context of the logistic growth model, \(f(0)\) represents the initial amount.
Step 7 :Final Answer: \(f(0)\) is \(\boxed{38.3}\) and it represents the initial amount.