Problem

Use the logistic growth model $f(x)=\frac{230}{1+5 e^{-2 x}}$.

Find $f(0)$. Round to the nearest tenth.

Interpret $f(0)$.
$f(0)$ represents the carrying capacity.
$f(0)$ represents the final amount.
$f(0)$ represents the rate of growth.
$f(0)$ represents the initial amount.
$f(0)$ represents the half life.

Answer

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Answer

Final Answer: \(f(0)\) is \(\boxed{38.3}\) and it represents the initial amount.

Steps

Step 1 :Use the logistic growth model \(f(x)=\frac{230}{1+5 e^{-2 x}}\).

Step 2 :Find \(f(0)\).

Step 3 :Calculate \(f(0)\) by substituting \(x = 0\) into the equation, which gives \(f(0) = \frac{230}{1+5 e^{0}}\).

Step 4 :Calculate the value of \(f(0)\) to get \(f(0) = 38.333333333333336\).

Step 5 :Round \(f(0)\) to the nearest tenth to get \(f(0) = 38.3\).

Step 6 :Interpret \(f(0)\). In the context of the logistic growth model, \(f(0)\) represents the initial amount.

Step 7 :Final Answer: \(f(0)\) is \(\boxed{38.3}\) and it represents the initial amount.

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