| Topic | Problem | Solution |
|---|---|---|
| None | What is the missing constant term in the perfect … | \( (x + a)^{2} = x^{2} + 2ax + a^{2} \) |
| None | Name 8-3 Additional Practice Solving Quadratic Eq… | \( x_{1} = \sqrt{64} \), \( x_{2} = -\sqrt{64} \) |
| None | Name: ID: A 40. Graph the function \( d=\sqrt{1.5… | Step 1: Plot the function \( d=\sqrt{1.5 h} \). |
| None | TEXAS INSTRUMENTS 11. antuo of \( \sin \left(-\fr… | \( \sin \left(-\frac{4 \pi}{3}\right) = \sin \left(\frac{2 \pi}{3}\right) \) |
| None | Name 8-4 Reteach to Build Understanding CTNies Co… | \begin{array}{ll} x^{2}-18 x+ (\frac{18}{2})^{2} & = 15+(\frac{18}{2})^{2} \\ x^{2}-18 x+ 81 & = 9… |
| None | 1) (30p) "x(t/3-2)" is given below in terms of u(… | \( x(t) = -3r(t-2) + 2u(t-3) + \delta(6t+9 + t^2) + 2\delta(t-5) -3r(t-5) \) |
| None | \( x=2 a \times \frac{2}{4}= \) | \(x = 2a \times \frac{2}{4}\) |
| None | \[ \begin{array}{r} 715 \\ +\quad 214 \\ \hline \… | (1) \( 5+4=9 \) |
| None | \( 0=5 \omega+\mapsto c \) | \( 0 = 5 \omega+c \) |
| None | (1) Add the ones digits: \( 5+4=9 \). (2) Add the… | Add the ones digits: 5+2 = 7. |
| None | The table shows the test scores for a class of st… | \(\frac{(3x + 2x + 42)}{5} = 5.35\) |
| None | Two-thousand ounces of a radioactive substance ar… | \( 50 = 2000 e^{-0.00043 t} \) |
| None | \[ x^{4}+3 x^{3}+2 x+1 \] What is the remainder w… | \(f(x) = x^4 + 3x^3 + 2x + 1\) |
| None | What is an equivalent form of \( (3-7 i)^{2} \) ? | \((3-7i)^2\) |
| None | Which number is equivalent to \( 16^{\frac{1}{2}}… | \( 16^{\frac{1}{2}} = \sqrt{16} \) |
| None | The grades on a history midterm at Almond are rou… | \( Z = \frac{X - \mu}{\sigma} \) |
| None | \[ -4 \cdot 3^{6 w}=-1750 \] What is the solution… | \(-4 \cdot 3^{6 w}=-1750\) |
| None | After a certain medicine is ingested, its concent… | \( C(t+1) = 78(0.62)^{(t+1)} \) |
| None | \( \sqrt[3]{8} \) | \( \sqrt[3]{8} = 8^{\frac{1}{3}} \) |
| None | using a \[ \sqrt{8} \] | Step 1: Find the prime factors of the radicand (number inside the square root): 8 = 2 * 2 * 2 |
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