ALL Problems

Topic Problem Solution
None If \( a_{1}=2 \) and \( a_{n}=\left(a_{n-1}\right… a_2 = (a_1)^2 - 2 = (2)^2 - 2 = 2
None If \( a_{1}=7 \) and \( a_{n}=3 a_{n-1}+3 \) then… \(a_2 = 3a_1 + 3 = 3 \times 7 + 3\)
None Write a recursive formula for \( a_{n} \), the \(… \(a_{1}=1\)
None Write a recursive formula for \( a_{n} \), the \(… a_{1}=19
None Is \( (-836,-63) \) a solution to the equation \(… Step 1: Substitute x = -836 and y = -63 into the equation y = -395x
None Select the equivalent expression. \[ \left(\frac{… \( \left(\frac{1}{s^{-1} \cdot s^{8}}\right)^{\frac{3}{14}} = \left(\frac{1}{s^{7}}\right)^{\frac{3…
None Select the equivalent expression. \[ \sqrt[18]{\f… \(\sqrt[18]{\frac{b^{-1}}{b^{8}}} = \sqrt[18]{b^{-1-8}}\)
None Select the equivalent expression. \[ \sqrt{\frac{… \sqrt{\frac{k^{5}}{k^{6}}}
None Select the equivalent expression. \[ \sqrt[4]{\fr… Simplify the expression inside the fourth root: \( \frac{z^{-5}}{z^{-4}} \)
None Select the equivalent expression. \[ \sqrt[15]{\f… Combine exponents in the denominator: \(\frac{1}{s^{6}\cdot s^{4}} = \frac{1}{s^{(6+4)}} = \frac{1}…
None Select the equivalent expression. \[ \left(\frac{… \( \left(\frac{1}{x^{-6} \cdot x^{-7}}\right)^{\frac{1}{52}} = \left(x^{6} \cdot x^{7}\right)^{\fra…
None Select the equivalent expression. \[ \sqrt[8]{\fr… \sqrt[8]{\frac{d^{-8}}{d^{-6}}} = \sqrt[8]{d^{-8} \cdot d^{6}}
None Select the equivalent expression. \[ \left(\frac{… \(\left(\frac{1}{z^{-3} \cdot z}\right)^{\frac{5}{2}} \)
None 3:54 p. m. Vie may. 12 \( A A \) Speedtest by Ook… \( \frac{5}{9} \times 63 \)
None \( 2^{-3}= \) \( 2^{-3} = 2^{-(3/1)} \)
None It takes 21 minutes for a certain population of b… \( T = 42 \textrm{ min} \)
None If \( \frac{3}{x-1}=2 \), then \( x= \) \( (x-1) \cdot \frac{3}{x-1} = 2 \cdot (x-1) \)
None \( \left(3 \times 10^{2}\right) \times\left(2 \ti… \( (3 \times 10^{2}) \times (2 \times 10^{-4}) = (3 \times 2) \times (10^{2} \times 10^{-4}) \)
None If \( x=2 \) and \( y=-3 \), then \( -x y^{2}= \) \(-x y^{2} = -(2)(-3)^{2}\)
None A square playground has sides that each measure 1… \( \text{Scale Ratio} = \frac{\text{Length on Drawing}}{\text{Length on Playground}} \)

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