From a group of 6 people, 2 are randomly selected. What is the probability the 2 oldest people in the group were selected? Give your answer as a reduced fraction.

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Question 6

Step 1 ：The problem is asking for the probability of selecting the two oldest people from a group of six. This is a combination problem, where order does not matter. The total number of ways to select 2 people from a group of 6 is given by the combination formula \(C(n, k) = \frac{n!}{k!(n-k)!}\), where n is the total number of items, k is the number of items to choose, and ! denotes factorial. In this case, n=6 and k=2. The event we are interested in (selecting the two oldest people) can occur in only one way. Therefore, the probability is given by the ratio of the number of favorable outcomes to the total number of outcomes.

Step 2 ：The total number of outcomes is 15.

Step 3 ：The number of favorable outcomes is 1.

Step 4 ：The probability is \(\frac{1}{15}\).

Step 5 ：Final Answer: The probability that the 2 oldest people in the group were selected is \(\boxed{\frac{1}{15}}\).