Find the equation of the line parallel to the line \(3x - 4y = 8\) and passing through the point \((4,2)\).

Step 1 ：Step 1: Rewrite the given line in slope-intercept form, \(y = mx + b\), to find the slope. Adding \(4y\) to both sides and then dividing by \(4\) gives \(y = \frac{3}{4}x - 2\). So the slope of the given line is \(\frac{3}{4}\).

Step 2 ：Step 2: Since parallel lines have the same slope, the line we are looking for also has a slope of \(\frac{3}{4}\).

Step 3 ：Step 3: Using the slope-intercept form \(y = mx + b\), substitute the given point \((4,2)\) and the slope \(\frac{3}{4}\) into the equation to find the y-intercept \(b\). This gives \(2 = \frac{3}{4} * 4 + b\), so \(b = -1\).

Step 4 ：Step 4: Substitute the slope and y-intercept into the equation \(y = mx + b\) to get the equation of the line.