Evaluate the integral.
$${\int }_0^1\frac{x-1}{x^2-2x+5}dx$$
${\int }_0^1\frac{x-1}{x^2-2x+5}dx\approx$
(Type an integer or decimal rounded to three decimal places as needed.)

Step 1 ：The integral is a definite integral from 0 to 1. The integrand is a rational function.

Step 2 ：We can use numerical methods to approximate the value of the integral. One common method is Simpson's rule, which approximates the area under the curve by dividing it into a number of equal-width intervals and approximating the area of each interval with a parabola.

Step 3 ：We set n = 1000 and h = 0.001.

Step 4 ：We calculate the x values from 0 to 1 with a step of 0.001, and the corresponding y values using the function $\frac{x-1}{x^2-2x+5}$.

Step 5 ：We then calculate the integral using Simpson's rule and get an approximate value of -0.11157177565710732.

Step 6 ：The approximate value of the integral ${\int }_0^1\frac{x-1}{x^2-2x+5}dx$ is $\boxed{{\displaystyle -0.112}}$.