Find each of the following. Enter your answers rounded to at least two decimal places.
Part 1 of 5
$z_{\alpha / 2}$ for the $90 \%$ confidence interval
\[
z_{\alpha / 2}=\square
\]
The z-score for a 90% confidence interval is approximately \(\boxed{1.645}\).
Step 1 :We are asked to find the z-score for a 90% confidence interval. This is denoted as \(z_{\alpha / 2}\).
Step 2 :We use the scipy.stats library in Python to calculate the z-score. The function norm.ppf(0.95) is used because the z-score for a 90% confidence interval is the percentile point at 0.95 (or 95%).
Step 3 :The Python code returns a z-score of approximately 1.6448536269514722.
Step 4 :We round this to at least two decimal places to get the final answer.
Step 5 :The z-score for a 90% confidence interval is approximately \(\boxed{1.645}\).