f) ∫3x3−5x53dx
∫u(x)3du(x)dxdx=∫u13du
Step 1 :u(x)=3x3−5x5
Step 2 :du(x)dx=9x2−25x4
Step 3 :∫u(x)3du(x)dxdx=∫u13du