Evaluate $\int_{C}(x+y) d s, C: x=2 t, y=-2 t+2$, for $-1 \leq t \leq 1$
Thus, the value of the line integral over the curve C is \(\boxed{4}\)
Step 1 :Given the line integral \(\int_{C}(x+y) d s\), where the curve C is parameterized by \(x=2 t\) and \(y=-2 t+2\) for \(-1 \leq t \leq 1\)
Step 2 :Substitute the parameterizations of x and y into the integral to get \(\int_{C}(2t - 2t + 2) d s\)
Step 3 :Simplify the integral to \(\int_{C}2 ds\)
Step 4 :Calculate the integral of ds from -1 to 1 to get 4
Step 5 :Thus, the value of the line integral over the curve C is \(\boxed{4}\)