Use the balanced equation to solve the problem
\[
\mathrm{N}_{2}+3 \mathrm{H}_{2} \rightarrow 2 \mathrm{NH}_{3}
\]
\( 12.3 \mathrm{~g} \mathrm{NH}_{3} \) are made.
How many liters of \( \mathrm{H}_{2} \) gas reacted at STP?

Answer

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Answer

\( 1.0838 \times 22.4=24.2767 \mathrm{L}\)

Steps

Step 1 ：\( \frac{12.3}{17.031} \mathrm{mol} \mathrm{NH}_{3}=0.7225 \mathrm{mol} \mathrm{NH}_{3} \)

Step 2 ：\( \frac{3 \mathrm{mol} \mathrm{H}_{2}}{2 \mathrm{mol} \mathrm{NH}_{3}} \times 0.7225 \mathrm{mol} \mathrm{NH}_{3}=1.0838 \mathrm{mol} \mathrm{H}_{2} \)

Step 3 ：\( 1.0838 \times 22.4=24.2767 \mathrm{L}\)

Use the balanced equation to solve the problem\[\mathrm{N}_{2}+3 \mathrm{H}_{2} \rightarrow 2 \mathrm{NH}_{3}\]\( 12.3 \mathrm{~g} \mathrm{NH}_{3} \) are made.How many liters of \( \mathrm{H}_{2} \) gas reacted at STP?

Answer

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Use the balanced equation to solve the problem
\[
\mathrm{N}_{2}+3 \mathrm{H}_{2} \rightarrow 2 \mathrm{NH}_{3}
\]
\( 12.3 \mathrm{~g} \mathrm{NH}_{3} \) are made.
How many liters of \( \mathrm{H}_{2} \) gas reacted at STP?