Use the balanced equation to solve the problem
$N_{2} + 3 H_{2} \to 2 {NH}_{3}$
$12.3 g {NH}_{3}$ are made.
How many liters of $H_{2}$ gas reacted at STP?

Answer

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Answer

$1.0838 \times 22.4 = 24.2767 L$

Steps

Step 1 ： $\frac{12.3}{17.031} mol {NH}_{3} = 0.7225 mol {NH}_{3}$

Step 2 ： $\frac{3 mol H_{2}}{2 mol {NH}_{3}} \times 0.7225 mol {NH}_{3} = 1.0838 mol H_{2}$

Step 3 ： $1.0838 \times 22.4 = 24.2767 L$