left(frac{x+3}{(x+1)}right)^{prime}

Question

Accepted Answer

Step:1 ：Given function: (frac{x+3}{x+1})Step:2 ：Find the derivative using the quotient rule: (frac{f&#x27;(x)g(x) - f(x)g&#x27;(x)}{(g(x))^2})Step:3 ：Compute the derivatives: (f&#x27;(x) = 1) and (g&#x27;(x) = 1)Step:4 ：Apply the quotient rule: (frac{1(x+1) - (x+3)(1)}{(x+1)^2})Step:5 ：Simplify the expression: (frac{-2}{(x+1)^2})Step:6 ：(boxed{frac{-2}{(x+1)^2}})

Answer

Step: 1 ：Given function: (frac{x+3}{x+1})Step: 2 ：Find the derivative using the quotient rule: (frac{f&#x27;(x)g(x) - f(x)g&#x27;(x)}{(g(x))^2})Step: 3 ：Compute the derivatives: (f&#x27;(x) = 1) and (g&#x27;(x) = 1)Step: 4 ：Apply the quotient rule: (frac{1(x+1) - (x+3)(1)}{(x+1)^2})Step: 5 ：Simplify the expression: (frac{-2}{(x+1)^2})Step: 6 ：(boxed{frac{-2}{(x+1)^2}})

${(\frac{x + 3}{(x + 1)})}^{'}$

Answer

Popular Problems

(x+3(x+1))′

Answer

Popular Problems

${(\frac{x + 3}{(x + 1)})}^{'}$