Given that $f(x)=x^2-6x$ and $g(x)=x+4$, find
(a) $f+g=$
(b) $f-g=$
(c) $fg=$
(d) $f/g=$

Step 1 ：Given that $f(x)=x^2-6x$ and $g(x)=x+4$

Step 2 ：For part (a), we need to add the functions $f(x)$ and $g(x)$. This means we add the corresponding terms of the functions. So, $f+g=x^2-6x+x+4=x^2-5x+4$

Step 3 ：For part (b), we need to subtract the function $g(x)$ from $f(x)$. This means we subtract the corresponding terms of $g(x)$ from $f(x)$. So, $f-g=x^2-6x-(x+4)=x^2-7x-4$

Step 4 ：For part (c), we need to multiply the functions $f(x)$ and $g(x)$. This means we multiply each term of $f(x)$ with each term of $g(x)$ and then add the results. So, $fg=(x^2-6x)(x+4)=x^3-2x^2-24x$

Step 5 ：For part (d), we need to divide the function $f(x)$ by $g(x)$. This means we divide each term of $f(x)$ by $g(x)$. So, $f/g=(x^2-6x)/(x+4)$

Step 6 ：Final Answer: (a) $f+g=\boxed{{\displaystyle x^2-5x+4}}$ (b) $f-g=\boxed{{\displaystyle x^2-7x-4}}$ (c) $fg=\boxed{{\displaystyle x^3-2x^2-24x}}$ (d) $f/g=\boxed{{\displaystyle \frac{x^2-6x}{x+4}}}$