( f^{prime}(2), f^{prime}(x) ) ج ( f(x)=left(x^{3}+3 x^{2}-3right)^{frac{3}{2}} )

Question

Accepted Answer

Step:1 ：(f&#x27;(x) = frac{3}{2}(x^3 + 3x^2 - 3)^{frac{1}{2}} times (3x^2 + 6x))Step:2 ：(f&#x27;(2) = frac{3}{2}(2^3 + 3(2)^2 - 3)^{frac{1}{2}} times (3(2)^2 + 6(2)))Step:3 ：(f&#x27;(2) = frac{3}{2}(8 + 12 - 3)^{frac{1}{2}} times (12 + 12))Step:4 ：(f&#x27;(2) = frac{3}{2}(17)^{frac{1}{2}} times 24)Step:5 ：(f&#x27;(2) = 36sqrt{17})

Answer

Step: 1 ：(f&#x27;(x) = frac{3}{2}(x^3 + 3x^2 - 3)^{frac{1}{2}} times (3x^2 + 6x))Step: 2 ：(f&#x27;(2) = frac{3}{2}(2^3 + 3(2)^2 - 3)^{frac{1}{2}} times (3(2)^2 + 6(2)))Step: 3 ：(f&#x27;(2) = frac{3}{2}(8 + 12 - 3)^{frac{1}{2}} times (12 + 12))Step: 4 ：(f&#x27;(2) = frac{3}{2}(17)^{frac{1}{2}} times 24)Step: 5 ：(f&#x27;(2) = 36sqrt{17})

$f^{'} (2), f^{'} (x)$ ج $f (x) = {(x^{3} + 3 x^{2} - 3)}^{\frac{3}{2}}$

Answer

Popular Problems

f′(2),f′(x) ج f(x)=(x3+3x2−3)32

Answer

Popular Problems

$f^{'} (2), f^{'} (x)$ ج $f (x) = {(x^{3} + 3 x^{2} - 3)}^{\frac{3}{2}}$