What is the frequency of a beam of light traveling through a vacuum with a wavelength of \( 5 \times 10^{-4} \mathrm{~m} \) ? The speed of light in a vacuum is \( 3.00 \times 10^{8} \mathrm{~m} / \mathrm{s} \).
a \( 6.0 \times 10^{1< } \mathrm{Hz} \)
b \( 6.0 \times 10^{\pi 1} \mathrm{~Hz} \)
C \( 2.0 \times 10^{11} \mathrm{~Hz} \)
d \( 2.0 \times 10^{12} \mathrm{~Hz} \)
e \( 5.0 \times 10^{11} \mathrm{~Hz} \)

Answer

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Answer

\( f = 6.00 \times 10^{12} \mathrm{~Hz} \)

Steps

Step 1 ：\( f = \frac{c}{\lambda} \)

Step 2 ：\( f = \frac{3.00 \times 10^{8} \mathrm{~m} / \mathrm{s}}{5 \times 10^{-4} \mathrm{~m}} \)

Step 3 ：\( f = 6.00 \times 10^{12} \mathrm{~Hz} \)