Problem

3. Will a \( 120-\mathrm{kg} \) raft of density \( 700 \mathrm{~kg} / \mathrm{m}^{3} \) hold a \( 60-\mathrm{kg} \) person above water? Show all your work.

Answer

Expert–verified
Hide Steps
Answer

\(F_{buoyancy} = \rho_{water}\times V_{rafted}\times g = 1000 \times 0.1714\times 9.81 = 1113.49\ \mathrm{~kg}\)

Steps

Step 1 ：\(V = \frac{m}{\rho} = \frac{120}{700} = 0.1714\ \mathrm{m}^{3}\)

Step 2 ：\(A_{raft} = \frac{V}{h} = \frac{0.1714}{0.1} = 1.714\ \mathrm{m}^{2}\)

Step 3 ：\(m_{total} = 120 + 60 = 180\ \mathrm{kg}\)

Step 4 ：\(F_{buoyancy} = \rho_{water}\times V_{rafted}\times g = 1000 \times 0.1714\times 9.81 = 1113.49\ \mathrm{~kg}\)

link_gpt

Popular Problems

Compute $\int_{0}^{\ln (2) / … Solve the triangle. \[ \mathr… QUESTION 2 - 1 POINT Solve th… 5. Suppose you are a computer… Answer the statistical measur… $(-\infty, 2) \cap(-6, \infty… A firm does not pay a dividen… Math 112 Section: 4. Tubercul… Find $y^{\prime}$ if $y=\ln \… 3. (3pts) Cherry trees in a c… More