find out the value of \( x: x^{\wedge} 2-1=n d \) out the value of \( x: x^{\wedge} 2-1=0 \)
Solving Steps
Answer:
+1 find out the value of \( x \) :
\( x^{\wedge} 2-1=0 \) find out the value!!
\( x^{\wedge} 2-1=0+1 \) find out the value of \( x \) :
\( x^{\wedge} 2-1=0 \) find out the value of \( x \) :
\( x^{\wedge} 2-1=0 \)
(1) Add 1 to both sides of the equation: \( x^{\wedge} 2=1 \)
(2) Take the square root of both sides: \( x=\ddagger / 1 \)
(3) Take the square root of both sides: \( x=\ddagger / 1 \)
(4) Take the square root of both sides: \( x=\ddagger / 1 \)

Answer

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Answer

Take the square root of both sides: x=1 or x=-1

Steps

Step 1 ：To solve the quadratic equation x^2-1=0:

Step 2 ：Add 1 to both sides of the equation: x^2=1

Step 3 ：Take the square root of both sides: x=1 or x=-1