Solve the following system of equations with the substitution method:
\[
\left\{\begin{array}{l}
x+3 y=-1 \\
-3 x-4 y=5
\end{array}\right.
\]
Answer: $(x, y)=$
Preview $x$ :
Preview $y$ :
Enter your answers as integers or as reduced fractions in the form A/B.

Answer

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Answer

$\boxed{(x, y) = \left(-\frac{11}{5}, \frac{2}{5}\right)}$

Steps

Step 1 ：First, we solve the first equation for x: $x = -3y - 1$

Step 2 ：Next, we substitute this expression for x into the second equation: $-3(-3y - 1) - 4y = 5$

Step 3 ：Solving this equation gives us $y = \frac{2}{5}$

Step 4 ：Substituting $y = \frac{2}{5}$ back into the first equation gives us $x = -\frac{11}{5}$

Step 5 ：$\boxed{(x, y) = \left(-\frac{11}{5}, \frac{2}{5}\right)}$