Solve the following system by the substitution method.
\[
\begin{array}{l}
x+y=3 \\
y=x^{2}-17
\end{array}
\]
Select the correct choice below and, if necessary, fill in the answer box to complete your choice.
A. The solution set is
(Type an ordered pair. Use a comma to separate answers as needed. Simplify your answer.)
B. There is no solution.

Step 1 ：First, we can express \(x\) in terms of \(y\) from the first equation: \(x = 3 - y\).

Step 2 ：Next, we substitute \(x\) into the second equation: \(y = (3 - y)^{2} - 17\).

Step 3 ：This simplifies to: \(y = 9 - 6y + y^{2} - 17\).

Step 4 ：Rearranging terms, we get a quadratic equation: \(y^{2} + 7y - 8 = 0\).

Step 5 ：We can solve this quadratic equation by factoring: \((y - 1)(y + 8) = 0\).

Step 6 ：So, the solutions for \(y\) are \(y = 1\) and \(y = -8\).

Step 7 ：For \(y = 1\), we substitute back into the first equation to find \(x\): \(x = 3 - 1 = 2\).

Step 8 ：For \(y = -8\), we substitute back into the first equation to find \(x\): \(x = 3 - (-8) = 11\).

Step 9 ：Thus, the solution set is \(\boxed{(2,1)}\) and \(\boxed{(11,-8)}\).