A 6000 -seat theater has tickets for sale at $$ 28$ and $$ 40$ . How many tickets should be sold at each price for a sellout performance to generate a total revenue of $$ 194, 400$ ?
The number of tickets for sale at $$ 28$ should be

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Final Answer: The number of tickets for sale at $28 should be $3800$ .

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Step 1 ：Let's denote the number of tickets sold at $28 a s x a n d t h e n u m b e r o f t i c k e t s s o l d a t$ 40 as y. We know that the total number of tickets is 6000, so we have the equation $x + y = 6000$ . We also know that the total revenue is $194,400, so we have the equation $28 x + 40 y = 194400$ . We can solve this system of equations to find the values of x and y.

Step 2 ：The solution to the system of equations is $x = 3800$ and $y = 2200$ . This means that 3800 tickets should be sold at $28 a n d 2200 t i c k e t s s h o u l d b e s o l d a t$ 40 to generate a total revenue of $194,400.

Step 3 ：Final Answer: The number of tickets for sale at $28 should be $3800$ .

A 6000 -seat theater has tickets for sale at $28 and $40. How many tickets should be sold at each price for a sellout performance to generate a total revenue of $194,400 ?The number of tickets for sale at $28 should be

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A 6000 -seat theater has tickets for sale at $$ 28$ and $$ 40$ . How many tickets should be sold at each price for a sellout performance to generate a total revenue of $$ 194, 400$ ?
The number of tickets for sale at $$ 28$ should be