Bo is flying a kite, holding his hands a distance of 3.5 feet above the ground and letting all the kite's string play out. He measures the angle of elevation from his hand to the kite to be $29^{\circ}$. If the string from the kite to his hand is 110 feet long, how many feet is the kite above the ground? Round your answer to the nearest tenth of a foot if necessary.
Answer
\(\boxed{56.8}\) feet above the ground
Step 1 ：Find the height of the kite above Bo's hand using sine function: height_above_hand = \(\sin(29^\circ) \times 110\)
Step 2 ：Add the height of Bo's hand above the ground to find the total height of the kite above the ground: total_height = height_above_hand + 3.5
Step 3 ：Calculate the height_above_hand: \(\sin(29^\circ) \times 110 \approx 53.3\)
Step 4 ：Calculate the total_height: \(53.3 + 3.5 = 56.8\)
Step 5 ：\(\boxed{56.8}\) feet above the ground
