Problem

Bo is flying a kite, holding his hands a distance of 3.5 feet above the ground and letting all the kite's string play out. He measures the angle of elevation from his hand to the kite to be 29∘. If the string from the kite to his hand is 110 feet long, how many feet is the kite above the ground? Round your answer to the nearest tenth of a foot if necessary.

Answer

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Answer

56.8 feet above the ground

Steps

Step 1 ：Find the height of the kite above Bo's hand using sine function: height_above_hand = sin⁡(29∘)×110

Step 2 ：Add the height of Bo's hand above the ground to find the total height of the kite above the ground: total_height = height_above_hand + 3.5

Step 3 ：Calculate the height_above_hand: sin⁡(29∘)×110≈53.3

Step 4 ：Calculate the total_height: 53.3+3.5=56.8

Step 5 ：56.8 feet above the ground

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