Find the value of each trigonometric ratio.5) sinZA) 125B) 513C) 1312D) 512
\boxed{\frac{12}{13}}
Step 1 :sin2Z+cos2Z=1
Step 2 :sin2Z=1−cos2Z
Step 3 :sin2Z=1−(513)2
Step 4 :sin2Z=1−25169
Step 5 :sin2Z=144169
Step 6 :sinZ=±1213
Step 7 :\boxed{\frac{12}{13}}