Problem

Find $f_{x}$ and $f_{y}$ for $f(x, y)=\frac{4 x}{9 y}-\frac{2 y}{5 x}$
\[
\begin{array}{l}
f_{x}= \\
f_{y}=
\end{array}
\]

Answer

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Answer

\(\boxed{f_{y}=-\frac{4x}{9y^{2}} - \frac{2}{5x}}\)

Steps

Step 1 :Given the function \(f(x, y)=\frac{4 x}{9 y}-\frac{2 y}{5 x}\), we need to find the partial derivatives \(f_x\) and \(f_y\).

Step 2 :To find \(f_x\), we treat \(y\) as a constant and differentiate with respect to \(x\).

Step 3 :To find \(f_y\), we treat \(x\) as a constant and differentiate with respect to \(y\).

Step 4 :The partial derivative \(f_x\) is calculated as \(f_x = \frac{4}{9y} + \frac{2y}{5x^{2}}\).

Step 5 :The partial derivative \(f_y\) is calculated as \(f_y = -\frac{4x}{9y^{2}} - \frac{2}{5x}\).

Step 6 :Thus, the final answers are \(f_x = \frac{4}{9y} + \frac{2y}{5x^{2}}\) and \(f_y = -\frac{4x}{9y^{2}} - \frac{2}{5x}\).

Step 7 :\(\boxed{f_{x}=\frac{4}{9y} + \frac{2y}{5x^{2}}}\)

Step 8 :\(\boxed{f_{y}=-\frac{4x}{9y^{2}} - \frac{2}{5x}}\)

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