Suppose that the function $g$ is defined, for all real numbers, as follows.
$$g(x)=\{\begin{array}{ll}-\frac{1}{4}x+1& \text{ if }x\ne -1\\ 2& \text{ if }x=-1\end{array}$$
Find $g(-3),g(-1)$, and $g(1)$.

Step 1 ：Let's find the values of the function g at -3, -1, and 1.

Step 2 ：For x = -3, since -3 is not equal to -1, we use the first part of the function definition. Substituting x = -3 into the equation $-\frac{1}{4}x+1$, we get $-\frac{1}{4}\ast (-3)+1=1.75$.

Step 3 ：For x = -1, since -1 is equal to -1, we use the second part of the function definition. So, g(-1) = 2.

Step 4 ：For x = 1, since 1 is not equal to -1, we use the first part of the function definition. Substituting x = 1 into the equation $-\frac{1}{4}x+1$, we get $-\frac{1}{4}\ast 1+1=0.75$.

Step 5 ：So, the values of the function g at -3, -1, and 1 are 1.75, 2, and 0.75 respectively.

Step 6 ：$\boxed{{\displaystyle g(-3)=1.75,g(-1)=2,g(1)=0.75}}$