Suppose that the function $g$ is defined, for all real numbers, as follows.
\[
g(x)=\left\{\begin{array}{ll}
-\frac{1}{4} x+1 & \text { if } x \neq-1 \\
2 & \text { if } x=-1
\end{array}\right.
\]
Find $g(-3), g(-1)$, and $g(1)$.

Step 1 ：Let's find the values of the function g at -3, -1, and 1.

Step 2 ：For x = -3, since -3 is not equal to -1, we use the first part of the function definition. Substituting x = -3 into the equation \(-\frac{1}{4}x + 1\), we get \(-\frac{1}{4}*(-3) + 1 = 1.75\).

Step 3 ：For x = -1, since -1 is equal to -1, we use the second part of the function definition. So, g(-1) = 2.

Step 4 ：For x = 1, since 1 is not equal to -1, we use the first part of the function definition. Substituting x = 1 into the equation \(-\frac{1}{4}x + 1\), we get \(-\frac{1}{4}*1 + 1 = 0.75\).

Step 5 ：So, the values of the function g at -3, -1, and 1 are 1.75, 2, and 0.75 respectively.

Step 6 ：\(\boxed{g(-3) = 1.75, g(-1) = 2, g(1) = 0.75}\)