left{begin{array}{l}x-2 y+z=1 y+2 z=-9 x+y+3 z=-14end{array}right.

Question

left{begin{array}{l}x-2 y+z=1  y+2 z=-9  x+y+3 z=-14end{array}right.

Accepted Answer

Step:1 ：Given the system of linear equations: (begin{cases} x-2y+z=1  y+2z=-9  x+y+3z=-14 end{cases})Step:2 ：We can represent this system in matrix form as: (begin{bmatrix} 1 & -2 & 1  0 & 1 & 2  1 & 1 & 3 end{bmatrix} begin{bmatrix} x  y  z end{bmatrix} = begin{bmatrix} 1  -9  -14 end{bmatrix})Step:3 ：Solving this system of equations, we find the solution to be: (x = -2, y = -3, z = -3)Step:4 ：Final Answer: (boxed{x = -2, y = -3, z = -3})

Answer

Step: 1 ：Given the system of linear equations: (begin{cases} x-2y+z=1  y+2z=-9  x+y+3z=-14 end{cases})Step: 2 ：We can represent this system in matrix form as: (begin{bmatrix} 1 & -2 & 1  0 & 1 & 2  1 & 1 & 3 end{bmatrix} begin{bmatrix} x  y  z end{bmatrix} = begin{bmatrix} 1  -9  -14 end{bmatrix})Step: 3 ：Solving this system of equations, we find the solution to be: (x = -2, y = -3, z = -3)Step: 4 ：Final Answer: (boxed{x = -2, y = -3, z = -3})

$\left\{\begin{array}{l}x-2 y+z=1 \\ y+2 z=-9 \\ x+y+3 z=-14\end{array}\right.$

Answer

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