Solve the system by the elimination/addition method
$\begin{array}{l} 3 x + 2 y = 10 \\ - 4 x - 3 y = - 13 \end{array}$

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Answer

Final Answer: $x = 4, y = - 1$

Steps

Step 1 ： $\begin{array}{l} 3 x + 2 y = 10 \\ - 4 x - 3 y = - 13 \end{array}$

Step 2 ： $\begin{array}{l} 12 x + 8 y = 40 \\ - 12 x - 9 y = - 39 \end{array}$

Step 3 ：Add the two equations: $- y = 1$

Step 4 ： $y = - 1$

Step 5 ：Substitute y into the first equation: $3 x + 2 (- 1) = 10$

Step 6 ： $3 x - 2 = 10$

Step 7 ： $x = 4$

Step 8 ：Final Answer: $x = 4, y = - 1$