Solve the system by the elimination/addition method
\[
\begin{array}{l}
3 x+2 y=10 \\
-4 x-3 y=-13
\end{array}
\]

Answer

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Answer

Final Answer: \(\boxed{x=4, y=-1}\)

Steps

Step 1 ：\(\begin{array}{l} 3x+2y=10 \\ -4x-3y=-13 \end{array}\)

Step 2 ：\(\begin{array}{l} 12x+8y=40 \\ -12x-9y=-39 \end{array}\)

Step 3 ：Add the two equations: \(-y=1\)

Step 4 ：\(\boxed{y=-1}\)

Step 5 ：Substitute y into the first equation: \(3x+2(-1)=10\)

Step 6 ：\(3x-2=10\)

Step 7 ：\(\boxed{x=4}\)

Step 8 ：Final Answer: \(\boxed{x=4, y=-1}\)