convert $2 x^{2}-3 x-2$ to vertex form
\(\boxed{y = 2\left(x - \frac{3}{4}\right)^2 - \frac{7}{8}}\)
Step 1 :Factor out the coefficient of the x^2 term: \(y = 2(x^2 - \frac{3}{2}x) - 2\)
Step 2 :Complete the square by adding and subtracting the square of half of the coefficient of the x term: \(y = 2\left(x^2 - \frac{3}{2}x + \left(\frac{-3}{4}\right)^2 - \left(\frac{-3}{4}\right)^2\right) - 2\)
Step 3 :Rewrite the equation in vertex form: \(y = 2\left(x - \frac{3}{4}\right)^2 - 2 + 2\left(\frac{-3}{4}\right)^2\)
Step 4 :Calculate the final equation: \(y = 2\left(x - \frac{3}{4}\right)^2 - \frac{7}{8}\)
Step 5 :\(\boxed{y = 2\left(x - \frac{3}{4}\right)^2 - \frac{7}{8}}\)