Listed below are systolic blood pressure measurements (in $mm Hg$ ) obtained from the same woman. Find the regression equation, letting the right arm blood pressure be the predictor $(x)$ variable. Find the best predicted systolic blood pressure in the left arm given that the systolic blood pressure in the right arm is $80 mm$ Hg. Use a significance level of 0.05 .
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The regression equation is $\hat{y} = 67.1 + 1.1 x$ .
(Round to one decimal place as needed.)
Given that the systolic blood pressure in the right arm is $80 mm Hg$ , the best predicted systolic blood pressure in the left arm is $◻ mm Hg$ . (Round to one decimal place as needed.)

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Answer

The best predicted systolic blood pressure in the left arm is $155.1 mm Hg$ .

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Step 1 ：Given the regression equation $\hat{y} = 67.1 + 1.1 x$ , where $\hat{y}$ is the predicted systolic blood pressure in the left arm and $x$ is the systolic blood pressure in the right arm.

Step 2 ：Substitute $x = 80$ into the regression equation and solve for $\hat{y}$ .

Step 3 ：Calculate $\hat{y} = 67.1 + 1.1 * 80$ .

Step 4 ：The best predicted systolic blood pressure in the left arm is $155.1 mm Hg$ .

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