Find the integral.
$$\int (9x^2-4x+5)dx$$
$$\int (9x^2-4x+5)dx=$$

Step 1 ：The integral of a function is found by applying the power rule of integration, which states that the integral of x^n dx is (1/(n+1))x^(n+1), and the integral of a constant times a function is the constant times the integral of the function. The integral of a constant is the constant times x.

Step 2 ：So, to find the integral of the given function, we will apply the power rule to each term separately.

Step 3 ：The integral of the function $9x^2-4x+5$ is $3x^3-2x^2+5x$. However, we must not forget to add the constant of integration, usually denoted as $C$, to our answer. This is because the derivative of a constant is zero, so when we take the integral, we can't know what the original constant was, and we include $C$ to account for this.

Step 4 ：Final Answer: $\boxed{{\displaystyle \int (9x^2-4x+5)dx=3x^3-2x^2+5x+C}}$