Problem

Find an equation of the tangent line to the graph of y=ex2 at the point (5,1e25).
y=

Answer

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Answer

y1e25=10e25(x5)

Steps

Step 1 :Find the derivative of the function using the chain rule: dydx=2xex2

Step 2 :Find the slope of the tangent line at the point (5,1e25) by plugging in x=5 into the derivative: m=10e25

Step 3 :Use the point-slope form of a line to find the equation of the tangent line: y1e25=10e25(x5)

Step 4 :y1e25=10e25(x5)

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