Problem

Express the equation in logarithmic form:
(a) $4^{3}=64$ is equivalent to $\log A=B$.
\[
A=
\]
and
\[
B=
\]
(b) $10^{-4}=0.0001$ is equivalent to $\log _{10} C=D$.
\[
C=
\]
and
\[
D=
\]

Answer

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Answer

Final Answer: For the first part, \(\boxed{A = 64, B = 3}\). For the second part, \(\boxed{C = 0.0001, D = -4}\).

Steps

Step 1 :Express the equation in logarithmic form: $4^{3}=64$ is equivalent to $\log A=B$.

Step 2 :Identify the base, exponent, and result in the equation $4^{3}=64$. The base is 4, the exponent is 3, and the result is 64.

Step 3 :Convert the equation into logarithmic form: $\log_4 64 = 3$.

Step 4 :Assign the values to A and B: $A = 64$ and $B = 3$.

Step 5 :Express the equation in logarithmic form: $10^{-4}=0.0001$ is equivalent to $\log _{10} C=D$.

Step 6 :Identify the base, exponent, and result in the equation $10^{-4}=0.0001$. The base is 10, the exponent is -4, and the result is 0.0001.

Step 7 :Convert the equation into logarithmic form: $\log_{10} 0.0001 = -4$.

Step 8 :Assign the values to C and D: $C = 0.0001$ and $D = -4$.

Step 9 :Final Answer: For the first part, \(\boxed{A = 64, B = 3}\). For the second part, \(\boxed{C = 0.0001, D = -4}\).

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