Find the average value over the given interval.
$y = 9 e^{- x}; [0, 5]$
The average value is (Type an exact answer.)

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The average value of the function over the interval [0, 5] is approximately 1.788.

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Step 1 ：The average value of a function over an interval [a, b] is given by the formula: $\frac{1}{b - a} \int_{a}^{b} f (x) d x$

Step 2 ：In this case, the function is $y = 9 e^{- x}$ and the interval is [0, 5]. So we need to integrate the function from 0 to 5, and then divide by the length of the interval, which is 5 - 0 = 5.

Step 3 ：Let's calculate the average value: $a v e r a g e_v a l u e = 1.8 - 1.8 * e x p (- 5)$

Step 4 ：The average value of the function over the interval [0, 5] is approximately 1.788.

Find the average value over the given interval.y=9e−x;[0,5]The average value is (Type an exact answer.)

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Find the average value over the given interval.
$y = 9 e^{- x}; [0, 5]$
The average value is (Type an exact answer.)