For the function, find the point(s) on the graph at which the tangent line has slope 5
\[
y=\frac{1}{3} x^{3}-4 x^{2}+20 x+9
\]
The point(s) is/are
(Simplify your answer. Type an ordered pair. Use a comma to separate answers as needed.)

Step 1 ：Given the function \(y=\frac{1}{3} x^{3}-4 x^{2}+20 x+9\), we are asked to find the point(s) on the graph at which the tangent line has slope 5.

Step 2 ：The slope of the tangent line to the graph of a function at a particular point is given by the derivative of the function at that point.

Step 3 ：First, we find the derivative of the function, which is \(y'=x^{2}-8x+20\).

Step 4 ：Next, we set the derivative equal to 5 and solve for x, which gives us the x-coordinates of the points where the slope of the tangent line is 5. The solutions are \(x=3\) and \(x=5\).

Step 5 ：Finally, we substitute these x-coordinates back into the original function to find the corresponding y-coordinates. This gives us the points \((3, 42)\) and \((5, 50.67)\).

Step 6 ：Final Answer: The points on the graph at which the tangent line has slope 5 are \(\boxed{(3, 42)}\) and \(\boxed{(5, 50.67)}\).