Solve $2 x^{2}-20 x=8$ by completing the square. Show all steps.

Step 1 ：Rearrange the equation so that the x terms are on one side of the equation and the constant is on the other side. This gives us \(2x^2 - 20x - 8 = 0\).

Step 2 ：Divide all terms by the coefficient of \(x^2\), which is 2, to get \(x^2 - 10x - 4 = 0\).

Step 3 ：Take half of the coefficient of x, square it, and add it to both sides of the equation. The coefficient of x is -10, so half of it is -5, and squaring -5 gives us 25. Adding 25 to both sides gives us \(x^2 - 10x + 25 = 4 + 25\).

Step 4 ：Simplify to \((x - 5)^2 = 29\).

Step 5 ：Take the square root of both sides to solve for x. This gives us \(x - 5 = \pm \sqrt{29}\), so \(x = 5 \pm \sqrt{29}\).

Step 6 ：The solutions to the equation \(2x^2 - 20x = 8\) are \(x = \boxed{5 + \sqrt{29}}\) and \(x = \boxed{5 - \sqrt{29}}\).