x^{2}-25=0

Question

x^{2}-25=0

Accepted Answer

Step:1 ：Given the quadratic equation (x^{2}-25=0).Step:2 ：The general form of a quadratic equation is (ax^{2}+bx+c=0). In this case, a=1, b=0, and c=-25.Step:3 ：The solutions to a quadratic equation are given by the formula (x=frac{-bpmsqrt{b^{2}-4ac}}{2a}).Step:4 ：Substitute a=1, b=0, and c=-25 into the formula, we get (x=frac{-0pmsqrt{0^{2}-4*1*(-25)}}{2*1}).Step:5 ：Simplify the above expression, we get (x=frac{pmsqrt{100}}{2}).Step:6 ：Further simplify the above expression, we get (x=pm5).Step:7 ：(boxed{x = 5, x = -5}) are the solutions to the equation (x^{2}-25=0).

Answer

Step: 1 ：Given the quadratic equation (x^{2}-25=0).Step: 2 ：The general form of a quadratic equation is (ax^{2}+bx+c=0). In this case, a=1, b=0, and c=-25.Step: 3 ：The solutions to a quadratic equation are given by the formula (x=frac{-bpmsqrt{b^{2}-4ac}}{2a}).Step: 4 ：Substitute a=1, b=0, and c=-25 into the formula, we get (x=frac{-0pmsqrt{0^{2}-4*1*(-25)}}{2*1}).Step: 5 ：Simplify the above expression, we get (x=frac{pmsqrt{100}}{2}).Step: 6 ：Further simplify the above expression, we get (x=pm5).Step: 7 ：(boxed{x = 5, x = -5}) are the solutions to the equation (x^{2}-25=0).

$x^{2}-25=0$

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