Question 4 of 10
A survey asked 40 students if they play an instrument and if they are in band.
1.25 students play an instrument.
2. 20 students are in band.
3. 20 students are not in band.
Which table shows these data correctly entered in a two-way frequency table?

Step 1 ：Given data: \(40\) students in total, \(25\) students play an instrument, \(20\) students are in band, and \(20\) students are not in band.

Step 2 ：Create a two-way frequency table with the given data.

Step 3 ：Since there are \(40\) students in total and \(20\) students are in band, there must be \(40 - 20 = 20\) students not in band.

Step 4 ：Since there are \(25\) students who play an instrument and \(20\) students are in band, there must be \(25 - 20 = 5\) students who play an instrument and are in band.

Step 5 ：Since there are \(25\) students who play an instrument and \(5\) students who play an instrument and are in band, there must be \(25 - 5 = 20\) students who play an instrument and are not in band.

Step 6 ：Since there are \(20\) students who are not in band and \(20\) students who play an instrument and are not in band, there must be \(20 - 20 = 0\) students who do not play an instrument and are not in band.

Step 7 ：Since there are \(40\) students in total and \(25\) students who play an instrument, there must be \(40 - 25 = 15\) students who do not play an instrument.

Step 8 ：Since there are \(15\) students who do not play an instrument and \(0\) students who do not play an instrument and are not in band, there must be \(15 - 0 = 15\) students who do not play an instrument and are in band.

Step 9 ：Final Answer: The two-way frequency table is as follows: \[\begin{array}{c|c|c|c} & \text{Band} & \text{Not Band} & \text{Total} \\ \hline \text{Instrument} & \boxed{5} & \boxed{20} & \boxed{25} \\ \hline \text{Not Instrument} & \boxed{15} & \boxed{0} & \boxed{15} \\ \hline \text{Total} & \boxed{20} & \boxed{20} & \boxed{40} \end{array}\]