Determine the equation of a quadratic relation in vertex form. given the following information.
a) vertex at $(0,3)$, passes through $(2,-5)$
\(\boxed{y = -2x^2 + 3}\) is the equation of the quadratic relation in vertex form.
Step 1 :Given the vertex form of a quadratic relation: \(y = a(x - h)^2 + k\), where \((h, k)\) is the vertex of the parabola.
Step 2 :Substitute the given vertex \((0, 3)\) into the equation: \(y = a(x - 0)^2 + 3\) or \(y = ax^2 + 3\).
Step 3 :Use the given point \((2, -5)\) to find the value of \(a\): \(-5 = a(2^2) + 3\).
Step 4 :Solve for \(a\): \(-5 = 4a + 3\) => \(a = -2\).
Step 5 :Substitute the value of \(a\) back into the equation: \(y = -2x^2 + 3\).
Step 6 :\(\boxed{y = -2x^2 + 3}\) is the equation of the quadratic relation in vertex form.