(b) Let A(x)=(x−2)2(3x−4)2 Find A′(x) in fully factorised form
A′(x)=(x−2)2(18x−24)+2(x−2)(3x−4)2
Step 1 :Let A(x)=(x−2)2(3x−4)2
Step 2 :Find the derivatives of (x−2)2 and (3x−4)2 using the chain rule:
Step 3 :ddx(x−2)2=2(x−2)
Step 4 :ddx(3x−4)2=2(3x−4)(3)
Step 5 :Apply the product rule to find A′(x):
Step 6 :A′(x)=(x−2)2(2(3x−4)(3))+(2(x−2))(3x−4)2
Step 7 :Simplify the expression:
Step 8 :A′(x)=(x−2)2(6(3x−4))+2(x−2)(3x−4)2
Step 9 :A′(x)=(x−2)2(18x−24)+2(x−2)(3x−4)2