int frac{d z}{s^{2} sqrt{s^{2}-9}}

Question

Accepted Answer

Step:1 ：Given the integral: (int frac{d z}{s^{2} sqrt{s^{2}-9}})Step:2 ：The integral of the function with respect to z is: (frac{z}{s^{2} sqrt{s^{2}-9}} + C)Step:3 ：(boxed{frac{z}{s^{2} sqrt{s^{2}-9}} + C})

Answer

Step: 1 ：Given the integral: (int frac{d z}{s^{2} sqrt{s^{2}-9}})Step: 2 ：The integral of the function with respect to z is: (frac{z}{s^{2} sqrt{s^{2}-9}} + C)Step: 3 ：(boxed{frac{z}{s^{2} sqrt{s^{2}-9}} + C})

$\int \frac{d z}{s^{2} \sqrt{s^{2}-9}}$

Answer

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