■Andrew Whittaker, computer center manager, reports that his computer system experienced three component failures during the past 100 days.
a. What is the probabifity of no failures in a given day?
b. What is the probability of one or more component failures in a given day?
c. What is the probability of at least two failures in a 3-day period?

Step 1 ：Calculate the average number of failures per day: \(\frac{3}{100} = 0.03\)

Step 2 ：a. Find the probability of no failures in a given day using the Poisson distribution formula: \(P(X=0) = e^{-0.03} \approx 0.9704\)

Step 3 ：b. Find the probability of one or more component failures in a given day: \(1 - P(X=0) \approx 1 - 0.9704 = 0.0296\)

Step 4 ：c. Calculate the average number of failures in a 3-day period: \(0.03 \times 3 = 0.09\)

Step 5 ：Find the probability of at least two failures in a 3-day period: \(1 - P(X=0) - P(X=1) = 1 - e^{-0.09} - (0.09 \times e^{-0.09}) \approx 0.0038\)

Step 6 ：\boxed{\text{Final Answer:}}

Step 7 ：a. \(\boxed{0.9704}\) is the probability of no failures in a given day.

Step 8 ：b. \(\boxed{0.0296}\) is the probability of one or more component failures in a given day.

Step 9 ：c. \(\boxed{0.0038}\) is the probability of at least two failures in a 3-day period.