Problem

In a certain Algebra 2 class of 24 students, 6 of them play basketball and 16 of them play baseball. There are 6 students who play neither sport. What is the probability that a student chosen randomly from the class plays both basketball and baseball?

Answer

Expert–verified
Hide Steps
Answer

Solving for x, we get \(x = 4\). So, the probability is \(\frac{4}{24} = \boxed{\frac{1}{6}}\)

Steps

Step 1 ：Let x be the number of students who play both sports. Then, we have the equation: \(6 + 16 - x = 18\)

Step 2 ：Solving for x, we get \(x = 4\). So, the probability is \(\frac{4}{24} = \boxed{\frac{1}{6}}\)

link_gpt

Popular Problems

Compute $\int_{0}^{\ln (2) / … Solve the triangle. \[ \mathr… QUESTION 2 - 1 POINT Solve th… 5. Suppose you are a computer… Answer the statistical measur… $(-\infty, 2) \cap(-6, \infty… A firm does not pay a dividen… Math 112 Section: 4. Tubercul… Find $y^{\prime}$ if $y=\ln \… 3. (3pts) Cherry trees in a c… More