Problem

Fid the value of $k$ such that the tangent line to the graph of $f (x) = \frac{k + x}{x^{2}}$ has slop 5 at $x = 2$

Answer

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Answer

$5 = \frac{- 2 (k + 2)}{8}$

Steps

Step 1 ： $f^{'} (x) = \frac{- 2 (k + x)}{x^{3}}$

Step 2 ： $f^{'} (2) = \frac{- 2 (k + 2)}{2^{3}}$

Step 3 ： $5 = \frac{- 2 (k + 2)}{8}$

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