Problem

Fid the value of \( k \) such that the tangent line to the graph of \( f(x)=\frac{k+x}{x^{2}} \) has slop 5 at \( x=2 \)

Answer

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Answer

\( 5 = \frac{-2(k+2)}{8} \)

Steps

Step 1 :\( f'(x) = \frac{-2(k+x)}{x^{3}} \)

Step 2 :\( f'(2) = \frac{-2(k+2)}{2^{3}} \)

Step 3 :\( 5 = \frac{-2(k+2)}{8} \)

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