Use the balanced equation to solve the problem.
\[
2 \mathrm{Al}_{2} \mathrm{O}_{3} \rightarrow 4 \mathrm{Al}+3 \mathrm{O}_{2}
\]
\( 2.80 \mathrm{~mol} \) of aluminum are produced.
How many moles of \( \mathrm{O}_{2} \) are made?
\( \mathrm{mol} \)

Answer

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Answer

x = 2.10 \mathrm{mol}

Steps

Step 1 ：\( \frac{3 \mathrm{O}_{2}}{4 \mathrm{Al}}=\frac{x \mathrm{mol}}{2.80 \mathrm{~mol}} \)

Step 2 ：x = \frac{3 \mathrm{O}_{2} \cdot 2.80 \mathrm{~mol}}{4 \mathrm{Al}}

Step 3 ：x = 2.10 \mathrm{mol}