- Suppose \( X \) is normal with mean 8.0 and standard deviation 5.0
- Find \( P(X< 8.6) \)
Answer
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Answer
\(P(X<8.6) = P(Z<0.12)\)
Steps
Step 1 ：\(Z = \frac{X - \mu}{\sigma}\)
Step 2 ：\(Z = \frac{8.6 - 8.0}{5.0}\)
Step 3 ：\(P(X<8.6) = P(Z<0.12)\)
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