Problem

The table shows the number, expressed in millions, of citizens who moved in 2004 , categorized by where they moved and whether they were an owner or a renter.

Find the probability, expressed as a decimal rounded to the nearest
Number of People in a Certain Country Who Moved in 2004, in Millions
\begin{tabular}{|c|c|c|c|}
\hline & $\begin{array}{c}\text { Moved to } \\
\text { Same } \\
\text { Region }\end{array}$ & $\begin{array}{c}\text { Moved to } \\
\text { Different } \\
\text { Region }\end{array}$ & $\begin{array}{c}\text { Moved to } \\
\text { Different } \\
\text { Country }\end{array}$ \\
\hline Owner & 11.8 & 2.7 & 0.3 \\
\hline Renter & 18.7 & 4.5 & 1.0 \\
\hline
\end{tabular}
hundredth, that a randomly selected citizen who moved in 2004 was a renter who moved within the same region.
$\mathrm{P}($ citizen was a renter who moved within the same region $) \approx$ (Round to the nearest hundredth as needed.)

Answer

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Answer

So, the probability that a randomly selected citizen who moved in 2004 was a renter who moved within the same region is approximately \(\boxed{0.48}\).

Steps

Step 1 :First, we need to calculate the total number of people who moved in 2004. This is done by adding up all the numbers in the table: \(11.8 + 2.7 + 0.3 + 18.7 + 4.5 + 1.0 = 39.0\) million people.

Step 2 :Next, we find the number of renters who moved within the same region. From the table, we can see that this number is 18.7 million people.

Step 3 :The probability that a randomly selected citizen who moved in 2004 was a renter who moved within the same region is then given by the ratio of the number of renters who moved within the same region to the total number of people who moved. This is calculated as \(\frac{18.7}{39.0} = 0.47948717948717945\).

Step 4 :Rounding this to the nearest hundredth, we get \(0.48\).

Step 5 :So, the probability that a randomly selected citizen who moved in 2004 was a renter who moved within the same region is approximately \(\boxed{0.48}\).

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