The table shows the distribution, by age and gender, of the 28.9 million people in a certain region who live alone. Use the data in the table to find the probability that a randomly selected person in the region is a woman in the 18-24 age range living alone.
\begin{tabular}{|l|r|c|c|c|c|c|c|}
\hline & $\begin{array}{l}\text { Ages } \\
\text { 18-24 }\end{array}$ & $\begin{array}{l}\text { Ages } \\
\mathbf{2 5 - 3 4}\end{array}$ & $\begin{array}{l}\text { Ages } \\
\mathbf{3 5 - 4 4}\end{array}$ & $\begin{array}{l}\text { Ages } \\
\mathbf{4 5 - 6 4}\end{array}$ & $\begin{array}{l}\text { Ages } \\
\mathbf{6 5 - 7 4}\end{array}$ & $\begin{array}{c}\text { Ages } \\
275\end{array}$ & Total \\
\hline Male & 0.6 & 2.2 & 2.9 & 4.6 & 1.8 & 1.7 & 13.8 \\
\hline Female & 0.5 & 1.4 & 1.2 & 5.0 & 2.1 & 4.9 & 15.1 \\
\hline Total & 1.1 & 3.6 & 4.1 & 9.6 & 3.9 & 6.6 & 28.9 \\
\hline
\end{tabular}
The probability is
(Type an integer or decimal rounded to the nearest hundredth as needed.)
Answer
Final Answer: The probability that a randomly selected person in the region is a woman in the 18-24 age range living alone is approximately \(\boxed{0.0173}\).
Step 1 ：The question is asking for the probability that a randomly selected person in the region is a woman in the 18-24 age range living alone. From the table, we can see that there are 0.5 million women in the 18-24 age range living alone. The total population of the region is 28.9 million.
Step 2 ：So, the probability can be calculated by dividing the number of women in the 18-24 age range living alone by the total population.
Step 3 ：\(\text{{probability}} = \frac{{\text{{women\_18\_24}}}}{{\text{{total\_population}}}}\)
Step 4 ：Substitute the given values into the equation.
Step 5 ：\(\text{{probability}} = \frac{{0.5}}{{28.9}}\)
Step 6 ：Simplify the right side of the equation to get the final answer.
Step 7 ：\(\text{{probability}} = 0.01730103806228374\)
Step 8 ：Final Answer: The probability that a randomly selected person in the region is a woman in the 18-24 age range living alone is approximately \(\boxed{0.0173}\).
