It is equally probable that the pointer on the spinner shown will land on any one of the eight regions, numbered 1 through 8 . If the pointer lands on a borderline, spin again. Find the probability that the pointer will stop on an odd number or a number greater than 5.
The probability is
(Type an integer or a fraction. Simplify your answer.)

Step 1 ：The problem is asking for the probability that the pointer will stop on an odd number or a number greater than 5. The odd numbers are 1, 3, 5, 7 and the numbers greater than 5 are 6, 7, 8. So, the favorable outcomes are 1, 3, 5, 6, 7, 8.

Step 2 ：There are 6 favorable outcomes. The total possible outcomes are 8 (since the spinner has 8 regions).

Step 3 ：So, the probability is the number of favorable outcomes divided by the total number of outcomes. This can be calculated as \(\frac{favorable\_outcomes}{total\_outcomes}\).

Step 4 ：Substituting the values, we get \(\frac{6}{8}\) which simplifies to \(\frac{3}{4}\) or 0.75.

Step 5 ：Final Answer: The probability that the pointer will stop on an odd number or a number greater than 5 is \(\boxed{\frac{3}{4}}\) or 0.75.