If you are dealt 3 cards from a shuffled deck of 52 cards, find the probability of getting one queen and two kings.
The probability is
(Round to six decimal places as needed.)

Step 1 ：We are given a shuffled deck of 52 cards and we are to find the probability of getting one queen and two kings when dealt 3 cards.

Step 2 ：The total number of ways to draw 3 cards from a deck of 52 is given by the combination formula $C(n,k)=\frac{n!}{k!(n-k)!}$, where n is the total number of items, k is the number of items to choose, and '!' denotes factorial. In this case, n=52 and k=3, which gives us a total of 22100 ways.

Step 3 ：The number of ways to draw one queen from four available is $C(4,1)$, which gives us 4 ways.

Step 4 ：The number of ways to draw two kings from four available is $C(4,2)$, which gives us 6 ways.

Step 5 ：The probability of both events occurring is the product of their individual probabilities. Therefore, the probability of drawing one queen and two kings is $\frac{C(4,1)\ast C(4,2)}{C(52,3)}$.

Step 6 ：Substituting the values we have, the probability is approximately 0.0010859728506787331.

Step 7 ：Final Answer: The probability of getting one queen and two kings when dealt 3 cards from a shuffled deck of 52 cards is approximately $\boxed{{\displaystyle 0.001086}}$.